4 Bit Parallel In Serial Out Shift Register Verilog Code

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Parallel in serial out Verilog Shift Register, odd behavior during. 8 bit parallel in serial out shift register. Verilog code of 4-bit register with parallel. I'm creating an n bit shift register. I've put a for loop to shift n times inside a process. My code is given below. Shift register parallel in serial out.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 module piso1 (sout,sin,clk ); output sout; input [ 3: 0 ]sin; input clk; wire [ 3: 0 ]q; inv u1 (p,sl ); and1 u2 (n,sin [ 1 ],p ); and1 u3 (r,sl,q [ 0 ] ); or1 u4 (s,n,r ); and1 u5 (t,sin [ 2 ],p ); and1 u6 (u,sl,q [ 1 ] ); or1 u7 (v,u,t ); and1 u8 (w,sin [ 3 ],p ); and1 u9 (y,sl,q [ 2 ] ); or1 u10 (z,w,y ); dff1 u11 (q [ 0 ],sin [ 0 ],clk ); dff1 u12 (q [ 1 ],s,clk ); dff1 u13 (q [ 2 ],v,clk ); dff1 u14 (q [ 3 ],z,clk ); assign sout = q [ 3 ]; endmodule Simulated Waveform for Parallel In – Serial Out Shift Register Tags:,.

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4 Bit Parallel In Serial Out Shift Register Verilog CodeShift

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